(1/64)^x=2^(3x+5)

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Solution for (1/64)^x=2^(3x+5) equation: 



(1/64)^x=2^(3x+5)

We move all terms to the left:

(1/64)^x-(2^(3x+5))=0



Domain of the equation: 64)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/64)^x-(2^(3x+5))=0

We multiply all the terms by the denominator


(+1-((2^(3x+5)))*64)^x=0

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